What is expand (((3x-5)^5))/(15) ?

The solution to expand (((3x-5)^5))/(15) is (81x^5)/5-135x^4+450x^3-750x^2+625x-625/3

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expand (((3x-5)^5))/(15)

expand

\frac{( ( 3 x - 5 ) ^{5} )}{15}

\frac{81 x ^{5}}{5} - 135 x^{4} + 450 x^{3} - 750 x^{2} + 625 x - \frac{625}{3}

Solution steps

\frac{( 3 x - 5 ) ^{5}}{15}

(3 x - 5)^{5} = 243 x^{5} - 2025 x^{4} + 6750 x^{3} - 11250 x^{2} + 9375 x - 3125

= \frac{243 x ^{5} - 2025 x ^{4} + 6750 x ^{3} - 11250 x ^{2} + 9375 x - 3125}{15}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{243 x ^{5} - 2025 x ^{4} + 6750 x ^{3} - 11250 x ^{2} + 9375 x - 3125}{15} = \frac{243 x ^{5}}{15} - \frac{2025 x ^{4}}{15} + \frac{6750 x ^{3}}{15} - \frac{11250 x ^{2}}{15} + \frac{9375 x}{15} - \frac{3125}{15}

= \frac{243 x ^{5}}{15} - \frac{2025 x ^{4}}{15} + \frac{6750 x ^{3}}{15} - \frac{11250 x ^{2}}{15} + \frac{9375 x}{15} - \frac{3125}{15}

\frac{243 x ^{5}}{15} = \frac{81 x ^{5}}{5}

\frac{2025 x ^{4}}{15} = 135 x^{4}

\frac{6750 x ^{3}}{15} = 450 x^{3}

\frac{11250 x ^{2}}{15} = 750 x^{2}

\frac{9375 x}{15} = 625 x

\frac{3125}{15} = \frac{625}{3}

= \frac{81 x ^{5}}{5} - 135 x^{4} + 450 x^{3} - 750 x^{2} + 625 x - \frac{625}{3}

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What is expand (((3x-5)^5))/(15) ?
The solution to expand (((3x-5)^5))/(15) is (81x^5)/5-135x^4+450x^3-750x^2+625x-625/3