What is expand (x=7,-2x^2y)(x=x^2+4) ?

The solution to expand (x=7,-2x^2y)(x=x^2+4) is x=x^2-8x^2y

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expand (x=7,-2x^2y)(x=x^2+4)

expand

(x = 7, - 2 x^{2} y) (x = x^{2} + 4)

x = x^{2} - 8 x^{2} y

Solution steps

(x = 7, - 2 x^{2} y) (x = x^{2} + 4)

= (7 =, x - 2 x^{2} y) (= x^{2} x + 4)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = x = 7,, b = - 2 x^{2} y, c = x = x^{2}, d = 4

x = 7, x = x^{2} + x = 7, 4 + (- 2 x^{2} y) x = x^{2} + (- 2 x^{2} y) \cdot 4

Apply minus-plus rules

+ (- a) = - a

x = 7, x = x^{2} + x = 7, 4 - 2 x^{2} x y = x^{2} - 2 \cdot 4 x^{2} y

Expand

x^{2} - 2 \cdot 4 x^{2} y : x^{2} - 8 x^{2} y

x = x^{2} - 8 x^{2} y

, (- x^{2} - 5 x + 6)

(- 8 k)^{2} - 4 (12) (k^{2})

\frac{( - 12 - 2 x ) ( 70 x + 420 )}{x}

\frac{h - 2}{2 ( 1 + 2 h )}

y (x y + y) (x - 1) y^{'} (x)

What is expand (x=7,-2x^2y)(x=x^2+4) ?
The solution to expand (x=7,-2x^2y)(x=x^2+4) is x=x^2-8x^2y