What is expand t(x)(x=1+1/((2t(x)))) ?

The solution to expand t(x)(x=1+1/((2t(x)))) is tx^2= 3/2

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expand t(x)(x=1+1/((2t(x))))

expand

t (x) (x = 1 + \frac{1}{( 2 t ( x ) )})

t x^{2} = \frac{3}{2}

Solution steps

t (x) (x = 1 + \frac{1}{( 2 t ( x ) )})

= t (x) (1 = x + \frac{1}{( 2 t ( x ) )})

Apply the distributive law:

a (b + c) = ab + a c

a = t (x), b = x = 1, c = \frac{1}{( 2 t ( x ) )}

t (x) x = 1 + t (x) \frac{1}{( 2 t ( x ) )}

t (x) x = 1 + \frac{1}{( 2 t ( x ) )} t (x)

Simplify

t (x) x = 1 + \frac{1}{( 2 t ( x ) )} t (x) : t x^{2} = \frac{3}{2}

t x^{2} = \frac{3}{2}

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What is expand t(x)(x=1+1/((2t(x)))) ?
The solution to expand t(x)(x=1+1/((2t(x)))) is tx^2= 3/2