What is expand ((x-1)(x^2+2))/x ?

The solution to expand ((x-1)(x^2+2))/x is x^2+2-x-2/x

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expand ((x-1)(x^2+2))/x

expand

\frac{( x - 1 ) ( x ^{2} + 2 )}{x}

x^{2} + 2 - x - \frac{2}{x}

Solution steps

\frac{( x - 1 ) ( x ^{2} + 2 )}{x}

Expand

(x - 1) (x^{2} + 2) : x^{3} + 2 x - x^{2} - 2

= \frac{x ^{3} + 2 x - x ^{2} - 2}{x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 2 x - x ^{2} - 2}{x} = \frac{x ^{3}}{x} + \frac{2 x}{x} - \frac{x ^{2}}{x} - \frac{2}{x}

= \frac{x ^{3}}{x} + \frac{2 x}{x} - \frac{x ^{2}}{x} - \frac{2}{x}

Cancel

\frac{x ^{3}}{x} : x^{2}

= x^{2} + \frac{2 x}{x} - \frac{x ^{2}}{x} - \frac{2}{x}

Cancel

\frac{2 x}{x} : 2

= x^{2} + 2 - \frac{x ^{2}}{x} - \frac{2}{x}

Cancel

\frac{x ^{2}}{x} : x

= x^{2} + 2 - x - \frac{2}{x}

d er (4 \cdot sin (x) - e, x)

(6 m - 4 n = 1, 2) (3 m + n = 9)

e^{i x} + e^{i (x + \frac{π}{8})}

\frac{3 ( 1 + 5 e ^{6 x} )}{1 - 5 e ^{6 x}}

\frac{d}{d s} ((K (s)) (s + 3))

What is expand ((x-1)(x^2+2))/x ?
The solution to expand ((x-1)(x^2+2))/x is x^2+2-x-2/x