What is expand ((2x+5)(x-3))/2 ?

The solution to expand ((2x+5)(x-3))/2 is x^2-x/2-15/2

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expand ((2x+5)(x-3))/2

expand

\frac{( 2 x + 5 ) ( x - 3 )}{2}

x^{2} - \frac{x}{2} - \frac{15}{2}

Solution steps

\frac{( 2 x + 5 ) ( x - 3 )}{2}

Expand

(2 x + 5) (x - 3) : 2 x^{2} - x - 15

= \frac{2 x ^{2} - x - 15}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} - x - 15}{2} = \frac{2 x ^{2}}{2} - \frac{x}{2} - \frac{15}{2}

= \frac{2 x ^{2}}{2} - \frac{x}{2} - \frac{15}{2}

Divide the numbers:

\frac{2}{2} = 1

= x^{2} - \frac{x}{2} - \frac{15}{2}

\frac{x + 8}{x ( x + 11 )}

t (x = x^{1} + t (x^{2} - x^{1}))

\frac{( 3 x - 2 ) ( 3 x + 1 )}{3}

(4 x^{- 1} \circ 3 x + 5) (x)

\frac{( ( x + 1 ) ( x - 2 ) )}{x - 1}

What is expand ((2x+5)(x-3))/2 ?
The solution to expand ((2x+5)(x-3))/2 is x^2-x/2-15/2