What is expand ((2+3x)^2)/4 ?

The solution to expand ((2+3x)^2)/4 is (9x^2)/4+3x+1

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expand ((2+3x)^2)/4

expand

\frac{( 2 + 3 x ) ^{2}}{4}

\frac{9 x ^{2}}{4} + 3 x + 1

Solution steps

\frac{( 2 + 3 x ) ^{2}}{4}

(2 + 3 x)^{2} = 4 + 12 x + 9 x^{2}

= \frac{4 + 12 x + 9 x ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 + 12 x + 9 x ^{2}}{4} = \frac{4}{4} + \frac{12 x}{4} + \frac{9 x ^{2}}{4}

= \frac{4}{4} + \frac{12 x}{4} + \frac{9 x ^{2}}{4}

Apply rule

\frac{a}{a} = 1

\frac{4}{4} = 1

= 1 + \frac{12 x}{4} + \frac{9 x ^{2}}{4}

Divide the numbers:

\frac{12}{4} = 3

= 1 + 3 x + \frac{9 x ^{2}}{4}

Rewrite in standard form

= \frac{9 x ^{2}}{4} + 3 x + 1

(5 x + 1 \circ x^{2} - 5) (- 4)

(e^{2 x} + 2 x e^{2 x}) (4 x e^{2 x})

\frac{( 1 )}{( ( z + 2 ) ( z ^{(2)} + 1 ) )}

- 2 (ln (\frac{x - 2}{x + 2}) + c)

R e (x + Y)^{4}

What is expand ((2+3x)^2)/4 ?
The solution to expand ((2+3x)^2)/4 is (9x^2)/4+3x+1