What is expand ((3x-1)^3)/9 ?

The solution to expand ((3x-1)^3)/9 is 3x^3-3x^2+x-1/9

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expand ((3x-1)^3)/9

expand

\frac{( 3 x - 1 ) ^{3}}{9}

3 x^{3} - 3 x^{2} + x - \frac{1}{9}

Solution steps

\frac{( 3 x - 1 ) ^{3}}{9}

(3 x - 1)^{3} = 27 x^{3} - 27 x^{2} + 9 x - 1

= \frac{27 x ^{3} - 27 x ^{2} + 9 x - 1}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} - 27 x ^{2} + 9 x - 1}{9} = \frac{27 x ^{3}}{9} - \frac{27 x ^{2}}{9} + \frac{9 x}{9} - \frac{1}{9}

= \frac{27 x ^{3}}{9} - \frac{27 x ^{2}}{9} + \frac{9 x}{9} - \frac{1}{9}

Divide the numbers:

\frac{27}{9} = 3

= 3 x^{3} - 3 x^{2} + \frac{9 x}{9} - \frac{1}{9}

Divide the numbers:

\frac{9}{9} = 1

= 3 x^{3} - 3 x^{2} + x - \frac{1}{9}

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What is expand ((3x-1)^3)/9 ?
The solution to expand ((3x-1)^3)/9 is 3x^3-3x^2+x-1/9