What are the solutions to the equation 2x^2=160 ?

The solutions to the equation 2x^2=160 are x=4sqrt(5),x=-4sqrt(5)

Find the zeros of 2x^2=160

The zeros of 2x^2=160 are x=4sqrt(5),x=-4sqrt(5)

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2 x^{2} = 160

x = 45, x = - 45

Solution steps

2 x^{2} = 160

Divide both sides by

2

x^{2} = 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 80, x = - 80

80 = 45

- 80 = - 45

x = 45, x = - 45

∣ x - 3 ∣ \leq 5

(x - 3)^{2} + 2 (x - 3) - 8 = 0

\frac{12}{- 3}

1 < 3 - 2 x < 7

\frac{( 2 x + 3 )}{4} - \frac{( 3 - x )}{5} = \frac{( x + 2 )}{2}

What are the solutions to the equation 2x^2=160 ?
The solutions to the equation 2x^2=160 are x=4sqrt(5),x=-4sqrt(5)
Find the zeros of 2x^2=160
The zeros of 2x^2=160 are x=4sqrt(5),x=-4sqrt(5)