What is the answer to ((2x+3))/4-((3-x))/5 =((x+2))/2 ?

The answer to ((2x+3))/4-((3-x))/5 =((x+2))/2 is x= 17/4

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((2x+3))/4-((3-x))/5 =((x+2))/2

\frac{( 2 x + 3 )}{4} - \frac{( 3 - x )}{5} = \frac{( x + 2 )}{2}

x = \frac{17}{4}

Solution steps

\frac{( 2 x + 3 )}{4} - \frac{( 3 - x )}{5} = \frac{( x + 2 )}{2}

\frac{2 x + 3}{4} - \frac{3 - x}{5} = \frac{( x + 2 )}{2}

Multiply by LCM

5 (2 x + 3) - 4 (- x + 3) = 10 (x + 2)

Expand

5 (2 x + 3) - 4 (- x + 3) : 14 x + 3

Expand

10 (x + 2) : 10 x + 20

14 x + 3 = 10 x + 20

Move

3

to the right side

14 x = 10 x + 17

Move

10 x

to the left side

4 x = 17

Divide both sides by

4

x = \frac{17}{4}

\frac{x ^{- 7}}{x ^{- 8}}

ln (\frac{1}{e ^{6}})

a (4) = - \frac{1}{16} (2)^{4 - 1}

x^{2} (x^{2} - 4) \geq 0

16 x^{3} y^{2} - 8 x^{2} y - 24 x^{4} y^{2} - 40 x^{2} y^{3}

What is the answer to ((2x+3))/4-((3-x))/5 =((x+2))/2 ?
The answer to ((2x+3))/4-((3-x))/5 =((x+2))/2 is x= 17/4
Solve for x: ((2x+3))/4-((3-x))/5 =((x+2))/2
The solution is x= 17/4