What is expand (2x-1)^2*(e^x(x-1)) ?

The solution to expand (2x-1)^2*(e^x(x-1)) is 4e^xx^3-8e^xx^2+5e^xx-e^x

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expand (2x-1)^2*(e^x(x-1))

expand

(2 x - 1)^{2} \cdot (e^{x} (x - 1))

4 e^{x} x^{3} - 8 e^{x} x^{2} + 5 e^{x} x - e^{x}

Solution steps

(2 x - 1)^{2} (e^{x} (x - 1))

Remove parentheses:

(a) = a

= (2 x - 1)^{2} e^{x} (x - 1)

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= e^{x} (4 x^{2} - 4 x + 1) (x - 1)

= e^{x} (4 x^{2} - 4 x + 1) (x - 1)

Expand

(4 x^{2} - 4 x + 1) (x - 1) : 4 x^{3} - 8 x^{2} + 5 x - 1

= e^{x} (4 x^{3} - 8 x^{2} + 5 x - 1)

Expand

e^{x} (4 x^{3} - 8 x^{2} + 5 x - 1) : 4 e^{x} x^{3} - 8 e^{x} x^{2} + 5 e^{x} x - e^{x}

= 4 e^{x} x^{3} - 8 e^{x} x^{2} + 5 e^{x} x - e^{x}

(e^{2 x} - e^{- x})^{2}

A (- 1, 2) Y B (7, - 4)

(- \frac{z}{t ^{2}} + 2 cos (2 t)) d t

(y - 9) - (y + 6 = 4 y)

\frac{( x - y ) ^{2} - z ^{2}}{x + y + z}

What is expand (2x-1)^2*(e^x(x-1)) ?
The solution to expand (2x-1)^2*(e^x(x-1)) is 4e^xx^3-8e^xx^2+5e^xx-e^x