What is expand (x+3)(3x-1)' ?

The solution to expand (x+3)(3x-1)' is x(3x-1)'+3(3x-1)'

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expand (x+3)(3x-1)'

expand

(x + 3) (3 x - 1)^{'}

x (3 x - 1)' + 3 (3 x - 1)'

Solution steps

(x + 3) (3 x - 1)^{'}

Apply the distributive law:

a (b + c) = ab + a c

a = (3 x - 1)^{'}, b = x, c = 3

= (3 x - 1)^{^{'}} x + (3 x - 1)^{^{'}} 3

= x (3 x - 1)^{^{'}} + 3 (3 x - 1)^{^{'}}

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What is expand (x+3)(3x-1)' ?
The solution to expand (x+3)(3x-1)' is x(3x-1)'+3(3x-1)'