What is expand dy(y=5x^2-3x+2 1/(x-1)) ?

The solution to expand dy(y=5x^2-3x+2 1/(x-1)) is ydy=5x^2-3xdy+(2dy)/(x-1)

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expand dy(y=5x^2-3x+2 1/(x-1))

expand

d y (y = 5 x^{2} - 3 x + 2 \frac{1}{x - 1})

y d y = 5 x^{2} - 3 x d y + \frac{2 d y}{x - 1}

Solution steps

d y (y = 5 x^{2} - 3 x + 2 \cdot \frac{1}{x - 1})

= d y (5 = y x^{2} - 3 x + 2 \cdot \frac{1}{x - 1})

Distribute parentheses

d yy = 5 x^{2} + d y (- 3 x) + d y \cdot 2 \cdot \frac{1}{x - 1}

Apply minus-plus rules

+ (- a) = - a

y d y = 5 x^{2} - 3 x d y + 2 \cdot \frac{1}{x - 1} d y

Expand

5 x^{2} - 3 x d y + 2 \cdot \frac{1}{x - 1} d y : 5 x^{2} - 3 x d y + \frac{2 d y}{x - 1}

y d y = 5 x^{2} - 3 x d y + \frac{2 d y}{x - 1}

\frac{9}{t ( t - 3 ) ^{2}}

(n - k - 1)! (n - k)

\frac{( - 2 t + 6 ) ( 2 t - 3 )}{t ^{2}}

(4, 2, 3) x (- 2, 0, - 1)

\frac{0.9 s}{( s - 0.1 ) ( x + 0.2 )}

What is expand dy(y=5x^2-3x+2 1/(x-1)) ?
The solution to expand dy(y=5x^2-3x+2 1/(x-1)) is ydy=5x^2-3xdy+(2dy)/(x-1)