What is expand (3i,-1j,-1k)x(2i,j,2k) ?

The solution to expand (3i,-1j,-1k)x(2i,j,2k) is 3ix(2*2i,,jk),-1*jx(2*2i,,jk),-1*kx(2*2i,,jk)

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expand (3i,-1j,-1k)x(2i,j,2k)

expand

(3 i, - 1 j, - 1 k) x (2 i, j, 2 k)

3 i x (2 \cdot 2 i,, jk), - 1 \cdot j x (2 \cdot 2 i,, jk), - 1 \cdot k x (2 \cdot 2 i,, jk)

Solution steps

(3 i, - 1 \cdot j, - 1 \cdot k) x (2 i, j, 2 k)

= x (3 i, - 1, j - 1 \cdot k) (2 \cdot 2 i,, jk)

Distribute parentheses

= x (2 i, j, 2 k) \cdot 3 i, x (2 i, j, 2 k) (- 1 \cdot j,) + x (2 i, j, 2 k) (- 1 \cdot k)

Apply minus-plus rules

+ (- a) = - a

= 3 i x (2 \cdot 2 i,, jk), - 1 \cdot j x (2 \cdot 2 i,, jk), - 1 \cdot k x (2 \cdot 2 i,, jk)

\frac{x ^{2} - 3 x - 1}{x ( x ^{2} + 9 )}

\frac{( 2 x - 1 ) ( 2 x + 1 )}{9 x ^{4}}

(3 y - 1) d y

\frac{1 - s ( 1 - p )}{1 - s ( 1 - x )}

\frac{( 3 c + 4 ) ( 3 c - 2 )}{144}

What is expand (3i,-1j,-1k)x(2i,j,2k) ?
The solution to expand (3i,-1j,-1k)x(2i,j,2k) is 3ix(2*2i,,jk),-1*jx(2*2i,,jk),-1*kx(2*2i,,jk)