What is expand ((t^2+1)(1-t))/(t^3+1) ?

The solution to expand ((t^2+1)(1-t))/(t^3+1) is (t^2-t^3+1-t)/(t^3+1)

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expand ((t^2+1)(1-t))/(t^3+1)

expand

\frac{( t ^{2} + 1 ) ( 1 - t )}{t ^{3} + 1}

\frac{t ^{2} - t ^{3} + 1 - t}{t ^{3} + 1}

Solution steps

\frac{( t ^{2} + 1 ) ( 1 - t )}{t ^{3} + 1}

Expand

(t^{2} + 1) (1 - t) : t^{2} - t^{3} + 1 - t

= \frac{t ^{2} - t ^{3} + 1 - t}{t ^{3} + 1}

\frac{( ( x - 1 ) ( x - 2 ) )}{2}

ln (a + e^{(x + y + z)^{2}})

(2 - 6) a + (3 - 6) b

\frac{2 ( 2 x - 3 )}{5}

(f \circ g) x^{2} (4 x - 7)

What is expand ((t^2+1)(1-t))/(t^3+1) ?
The solution to expand ((t^2+1)(1-t))/(t^3+1) is (t^2-t^3+1-t)/(t^3+1)