What is expand (6(x^2-x+1))/(x(2x-1)) ?

The solution to expand (6(x^2-x+1))/(x(2x-1)) is (6x^2-6x+6)/(2x^2-x)

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expand (6(x^2-x+1))/(x(2x-1))

expand

\frac{6 ( x ^{2} - x + 1 )}{x ( 2 x - 1 )}

\frac{6 x ^{2} - 6 x + 6}{2 x ^{2} - x}

Solution steps

\frac{6 ( x ^{2} - x + 1 )}{x ( 2 x - 1 )}

Expand

x (2 x - 1) : 2 x^{2} - x

= \frac{6 ( x ^{2} - x + 1 )}{2 x ^{2} - x}

Expand

6 (x^{2} - x + 1) : 6 x^{2} - 6 x + 6

= \frac{6 x ^{2} - 6 x + 6}{2 x ^{2} - x}

d x (- x + 7)

\frac{2 ( x + 1 )}{( x - 2 )}

2 x - \frac{x}{6}

w e^{i (wt + \frac{π}{2})}

\frac{21}{( x + 8 ) ( x - 4 )}

What is expand (6(x^2-x+1))/(x(2x-1)) ?
The solution to expand (6(x^2-x+1))/(x(2x-1)) is (6x^2-6x+6)/(2x^2-x)