What is expand ((2a-1)(4a-1)^2)/(32) ?

The solution to expand ((2a-1)(4a-1)^2)/(32) is a^3-a^2+(5a)/(16)-1/32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((2a-1)(4a-1)^2)/(32)

expand

\frac{( 2 a - 1 ) ( 4 a - 1 ) ^{2}}{32}

a^{3} - a^{2} + \frac{5 a}{16} - \frac{1}{32}

Solution steps

\frac{( 2 a - 1 ) ( 4 a - 1 ) ^{2}}{32}

(4 a - 1)^{2} = 16 a^{2} - 8 a + 1

= \frac{( 2 a - 1 ) ( 16 a ^{2} - 8 a + 1 )}{32}

Expand

(2 a - 1) (16 a^{2} - 8 a + 1) : 32 a^{3} - 32 a^{2} + 10 a - 1

= \frac{32 a ^{3} - 32 a ^{2} + 10 a - 1}{32}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{32 a ^{3} - 32 a ^{2} + 10 a - 1}{32} = \frac{32 a ^{3}}{32} - \frac{32 a ^{2}}{32} + \frac{10 a}{32} - \frac{1}{32}

= \frac{32 a ^{3}}{32} - \frac{32 a ^{2}}{32} + \frac{10 a}{32} - \frac{1}{32}

Divide the numbers:

\frac{32}{32} = 1

= a^{3} - a^{2} + \frac{10 a}{32} - \frac{1}{32}

Cancel

\frac{10 a}{32} : \frac{5 a}{16}

= a^{3} - a^{2} + \frac{5 a}{16} - \frac{1}{32}

\frac{sin ( ( n - 2 ) π )}{( n - 2 ) π}

\frac{4 x + 1}{x ^{2} ( x ^{2} + x + 1 )}

\frac{4}{( s + 4 ) ^{3}}

(4 t + e^{t}) (4 - t)

\frac{( x + 3 ) 7}{5}

What is expand ((2a-1)(4a-1)^2)/(32) ?
The solution to expand ((2a-1)(4a-1)^2)/(32) is a^3-a^2+(5a)/(16)-1/32