What is expand-3(4x+3+4(6x+1)=43) ?

The solution to expand-3(4x+3+4(6x+1)=43) is -84x-21=43

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expand-3(4x+3+4(6x+1)=43)

expand

- 3 (4 x + 3 + 4 (6 x + 1) = 43)

- 84 x - 21 = 43

Solution steps

- 3 (4 x + 3 + 4 (6 x + 1) = 43)

= - 3 (4 x + 3 + 4 \cdot 43 = (6 x + 1))

Distribute parentheses

(- 3) \cdot 4 x + (- 3) \cdot 3 + (- 3) \cdot 4 (6 x + 1) = 43

Apply minus-plus rules

+ (- a) = - a

- 3 \cdot 4 x - 3 \cdot 3 - 3 \cdot 4 (6 x + 1) = 43

Expand

- 3 \cdot 4 x - 3 \cdot 3 - 3 \cdot 4 (6 x + 1) : - 84 x - 21

- 84 x - 21 = 43

\frac{d}{d y} ((x) (x^{2} + y^{4}))

\frac{2 x ( x - 3 )}{x - 1}

\frac{( ( 15 c + 2 ) ( 15 c - 2 ) )}{9}

1 1^{2}

\frac{( m + 12 ) ^{2}}{( n + 2 ) ^{4}}

What is expand-3(4x+3+4(6x+1)=43) ?
The solution to expand-3(4x+3+4(6x+1)=43) is -84x-21=43