What is expand (x^2+Δx)^2-4(x+Δx) ?

The solution to expand (x^2+Δx)^2-4(x+Δx) is x^4+2Δx^3+Δ^2x^2-4x-4Δx

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expand (x^2+Δx)^2-4(x+Δx)

expand

(x^{2} + Δ x)^{2} - 4 (x + Δ x)

x^{4} + 2Δ x^{3} + Δ^{2} x^{2} - 4 x - 4Δ x

Solution steps

(x^{2} + Δ x)^{2} - 4 (x + Δ x)

Expand

- 4 (x + Δ x) : - 4 x - 4Δ x

= (x^{2} + Δ x)^{2} - 4 x - 4Δ x

(x^{2} + Δ x)^{2} : x^{4} + 2Δ x^{3} + Δ^{2} x^{2}

= x^{4} + 2Δ x^{3} + Δ^{2} x^{2} - 4 x - 4Δ x

(1 - e^{- 10 t}) U (t)

(\frac{d y}{d x} - 1)^{2}

\frac{- 3 x + x ^{3}}{3 ( x - 1 )}

(g \circ f) (x + 3) (3 x^{2} - 9)

(2 x^{2} + 3 y^{2}) e - x^{2} - y^{2}

What is expand (x^2+Δx)^2-4(x+Δx) ?
The solution to expand (x^2+Δx)^2-4(x+Δx) is x^4+2Δx^3+Δ^2x^2-4x-4Δx