What is expand (g\circ f)(x+3)(3x^2-9) ?

The solution to expand (g\circ f)(x+3)(3x^2-9) is 3\circ gfx^3+9\circ gfx^2-9\circ gfx-27\circ gf

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expand (g\circ f)(x+3)(3x^2-9)

expand

(g \circ f) (x + 3) (3 x^{2} - 9)

3 \circ g f x^{3} + 9 \circ g f x^{2} - 9 \circ g f x - 27 \circ g f

Solution steps

(g \circ f) (x + 3) (3 x^{2} - 9)

= (\circ g f) (x + 3) (3 x^{2} - 9)

Expand

(x + 3) (3 x^{2} - 9) : 3 x^{3} + 9 x^{2} - 9 x - 27

= (g \circ f) (3 x^{3} + 9 x^{2} - 9 x - 27)

Expand

(g \circ f) (3 x^{3} + 9 x^{2} - 9 x - 27) : 3 \circ g f x^{3} + 9 \circ g f x^{2} - 9 \circ g f x - 27 \circ g f

= 3 \circ g f x^{3} + 9 \circ g f x^{2} - 9 \circ g f x - 27 \circ g f

(2 x^{2} + 3 y^{2}) e - x^{2} - y^{2}

\frac{4}{( x - 4 ) ( x + 4 )}

\frac{36}{s ( s ^{2} + 10.8 s + 36 )}

\frac{1}{( x ) ( x - 1 + k )}

(t^{2} - cos (t)) d t

What is expand (g\circ f)(x+3)(3x^2-9) ?
The solution to expand (g\circ f)(x+3)(3x^2-9) is 3\circ gfx^3+9\circ gfx^2-9\circ gfx-27\circ gf