What is expand (t^2-cos(t))dt ?

The solution to expand (t^2-cos(t))dt is t^2dt-cos(t)dt

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expand (t^2-cos(t))dt

expand

(t^{2} - cos (t)) d t

t^{2} d t - cos (t) d t

Solution steps

(t^{2} - cos (t)) d t

Apply the distributive law:

a (b - c) = ab - a c

a = d t, b = t^{2}, c = cos (t)

= d t t^{2} - d t cos (t)

= t^{2} d t - cos (t) d t

(x + d) (x + e)

(e^{e^{x}}) \cdot (1 + e^{x})

- \frac{2 ( x ^{2} + 6 x - 7 )}{15}

^{'} 2 (x^{2} + 3 x - 4) (4 x + 3)

5^{7}

What is expand (t^2-cos(t))dt ?
The solution to expand (t^2-cos(t))dt is t^2dt-cos(t)dt