What is expand-(2(x^2+6x-7))/(15) ?

The solution to expand-(2(x^2+6x-7))/(15) is -(2x^2}{15}-\frac{4x)/5+14/15

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expand-(2(x^2+6x-7))/(15)

expand

- \frac{2 ( x ^{2} + 6 x - 7 )}{15}

- \frac{2 x ^{2}}{15} - \frac{4 x}{5} + \frac{14}{15}

Solution steps

- \frac{2 ( x ^{2} + 6 x - 7 )}{15}

Expand

2 (x^{2} + 6 x - 7) : 2 x^{2} + 12 x - 14

= - \frac{2 x ^{2} + 12 x - 14}{15}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + 12 x - 14}{15} = - (\frac{2 x ^{2}}{15}) - (\frac{12 x}{15}) - (- \frac{14}{15})

= - (\frac{2 x ^{2}}{15}) - (\frac{12 x}{15}) - (- \frac{14}{15})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{2 x ^{2}}{15} - \frac{12 x}{15} + \frac{14}{15}

Cancel

\frac{12 x}{15} : \frac{4 x}{5}

= - \frac{2 x ^{2}}{15} - \frac{4 x}{5} + \frac{14}{15}

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What is expand-(2(x^2+6x-7))/(15) ?
The solution to expand-(2(x^2+6x-7))/(15) is -(2x^2}{15}-\frac{4x)/5+14/15