What is expand e^{2t-4}h(t-4) ?

The solution to expand e^{2t-4}h(t-4) is e^{2t-4}th-4e^{2t-4}h

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expand e^{2t-4}h(t-4)

expand

e^{2 t - 4} h (t - 4)

e^{2 t - 4} t h - 4 e^{2 t - 4} h

Solution steps

e^{2 t - 4} h (t - 4)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{2 t - 4} h, b = t, c = 4

= e^{2 t - 4} h t - e^{2 t - 4} h \cdot 4

= e^{2 t - 4} t h - 4 e^{2 t - 4} h

4 (x + h) + 6

\frac{2 x + 2}{( x - 1 ) ^{2}}

\frac{1}{x ^{2} ( s - 1 )}

\frac{k ( 2 n + 1 - 2 k )}{n ^{2}}

(2 x + e^{x}) (x^{3} + 2 e^{x})

What is expand e^{2t-4}h(t-4) ?
The solution to expand e^{2t-4}h(t-4) is e^{2t-4}th-4e^{2t-4}h