What is expand (3(x^2-2x))/(x^2-2x+1) ?

The solution to expand (3(x^2-2x))/(x^2-2x+1) is (3x^2-6x)/(x^2-2x+1)

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expand (3(x^2-2x))/(x^2-2x+1)

expand

\frac{3 ( x ^{2} - 2 x )}{x ^{2} - 2 x + 1}

\frac{3 x ^{2} - 6 x}{x ^{2} - 2 x + 1}

Solution steps

\frac{3 ( x ^{2} - 2 x )}{x ^{2} - 2 x + 1}

Expand

3 (x^{2} - 2 x) : 3 x^{2} - 6 x

= \frac{3 x ^{2} - 6 x}{x ^{2} - 2 x + 1}

6 4^{\frac{1}{3}}

(x - 4) (- 2 x^{3} e^{- 2 x})

q (- 45) h (3, - 2)

(2 e^{x} + 2) \cdot (e^{x} + 2 x + 3)

\frac{2 ( - 6 + 4 y )}{3}

What is expand (3(x^2-2x))/(x^2-2x+1) ?
The solution to expand (3(x^2-2x))/(x^2-2x+1) is (3x^2-6x)/(x^2-2x+1)