What is expand (2x-5y=7,)(4x+2y=2) ?

The solution to expand (2x-5y=7,)(4x+2y=2) is 8x^2+4xy=2

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expand (2x-5y=7,)(4x+2y=2)

expand

(2 x - 5 y = 7,) (4 x + 2 y = 2)

8 x^{2} + 4 x y = 2

Solution steps

(2 x - 5 y = 7,) (4 x + 2 y = 2)

= (2 x - 5 \cdot 7 =, y) (4 x + 2 \cdot 2 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = - 5 y = 7,, c = 4 x, d = 2 y = 2

2 x \cdot 4 x + 2 x \cdot 2 y = 2 + (- 5 y = 7,) \cdot 4 x + (- 5 y = 7,) \cdot 2 y = 2

Apply minus-plus rules

+ (- a) = - a

2 \cdot 4 xx + 2 \cdot 2 x y = 2 - 5 y = 7, 4 x - 5 y = 7, 2 y = 2

Expand

2 \cdot 4 xx + 2 \cdot 2 x y : 8 x^{2} + 4 x y

8 x^{2} + 4 x y = 2

3 (3 x - 8 = 30)

9 cos (x y) (y + x \frac{d y}{d x})

(5 x^{2} + x + 5) e^{x}

\frac{15 ( x + 3 y ) - 2}{30 ( x + 3 y ) - 20}

21 + 18

What is expand (2x-5y=7,)(4x+2y=2) ?
The solution to expand (2x-5y=7,)(4x+2y=2) is 8x^2+4xy=2