What is expand 4(7p-3q=-2,8)+7(5q-4p=16) ?

The solution to expand 4(7p-3q=-2,8)+7(5q-4p=16) is 28p-12q=16

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expand 4(7p-3q=-2,8)+7(5q-4p=16)

expand

4 (7 p - 3 q = - 2, 8) + 7 (5 q - 4 p = 16)

28 p - 12 q = 16

Solution steps

4 (7 p - 3 q = - 2, 8) + 7 (5 q - 4 p = 16)

= 4 (7 p - 3 = q - 2 \cdot 8,) + 7 (5 q - 4 \cdot 16 = p)

Expand

4 (7 p - 3 q = - 2, 8) : 4 \cdot 7 p - 4 \cdot 3 q = - 4 \cdot 2, 8

4 \cdot 7 p - 4 \cdot 3 q = - 4 \cdot 2, 8 + 7 (5 q - 4 p = 16)

Expand

7 (5 q - 4 p = 16) : 35 q - 28 p = 16

4 \cdot 7 p - 4 \cdot 3 q = - 4 \cdot 2, 8 + 35 q - 28 p = 16

Expand

4 \cdot 7 p - 4 \cdot 3 q : 28 p - 12 q

28 p - 12 q = 16

\frac{x ^{2} + 5}{5 ( x + 1 )}

\frac{240}{( x + 1 ) ^{5}}

(\frac{2 i}{n})^{2}

\frac{1}{( a x + 1 ) x}

\frac{( 2 x ^{2} + x - 3 ) ( 2 x - 1 )}{3}

What is expand 4(7p-3q=-2,8)+7(5q-4p=16) ?
The solution to expand 4(7p-3q=-2,8)+7(5q-4p=16) is 28p-12q=16