What is expand ((3y-a)^3)/(27) ?

The solution to expand ((3y-a)^3)/(27) is y^3-ay^2+(a^2y)/3-(a^3)/(27)

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expand ((3y-a)^3)/(27)

expand

\frac{( 3 y - a ) ^{3}}{27}

y^{3} - a y^{2} + \frac{a ^{2} y}{3} - \frac{a ^{3}}{27}

Solution steps

\frac{( 3 y - a ) ^{3}}{27}

(3 y - a)^{3} = 27 y^{3} - 27 a y^{2} + 9 a^{2} y - a^{3}

= \frac{27 y ^{3} - 27 a y ^{2} + 9 a ^{2} y - a ^{3}}{27}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 y ^{3} - 27 a y ^{2} + 9 a ^{2} y - a ^{3}}{27} = \frac{27 y ^{3}}{27} - \frac{27 a y ^{2}}{27} + \frac{9 a ^{2} y}{27} - \frac{a ^{3}}{27}

= \frac{27 y ^{3}}{27} - \frac{27 a y ^{2}}{27} + \frac{9 a ^{2} y}{27} - \frac{a ^{3}}{27}

Divide the numbers:

\frac{27}{27} = 1

= y^{3} - a y^{2} + \frac{9 a ^{2} y}{27} - \frac{a ^{3}}{27}

Cancel

\frac{9 a ^{2} y}{27} : \frac{a ^{2} y}{3}

= y^{3} - a y^{2} + \frac{a ^{2} y}{3} - \frac{a ^{3}}{27}

(d - 2) e^{3}

+ 6 (- 3 x^{2} e^{- 3 x} + 2 x e^{- 3 x})

x 2 + 8 x + 16

\frac{- s + 11}{10 ( s ^{2} + s + 8 )}

(a + 1)^{2} + b^{2}

What is expand ((3y-a)^3)/(27) ?
The solution to expand ((3y-a)^3)/(27) is y^3-ay^2+(a^2y)/3-(a^3)/(27)