What is expand 2((1-4y)/3)^2 ?

The solution to expand 2((1-4y)/3)^2 is (32y^2)/9-(16y)/9+2/9

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expand 2((1-4y)/3)^2

expand

2 (\frac{1 - 4 y}{3})^{2}

\frac{32 y ^{2}}{9} - \frac{16 y}{9} + \frac{2}{9}

Solution steps

2 (\frac{1 - 4 y}{3})^{2}

(\frac{1 - 4 y}{3})^{2} = \frac{1 - 8 y + 16 y ^{2}}{3 ^{2}}

= 2 \cdot \frac{16 y ^{2} - 8 y + 1}{3 ^{2}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 - 8 y + 16 y ^{2} ) \cdot 2}{3 ^{2}}

3^{2} = 9

= \frac{2 ( 16 y ^{2} - 8 y + 1 )}{9}

Expand

(1 - 8 y + 16 y^{2}) \cdot 2 : 2 - 16 y + 32 y^{2}

= \frac{2 - 16 y + 32 y ^{2}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 - 16 y + 32 y ^{2}}{9} = \frac{2}{9} - \frac{16 y}{9} + \frac{32 y ^{2}}{9}

= \frac{2}{9} - \frac{16 y}{9} + \frac{32 y ^{2}}{9}

Rewrite in standard form

= \frac{32 y ^{2}}{9} - \frac{16 y}{9} + \frac{2}{9}

\frac{5 x - 11}{( x + 1 ) ( x + 5 )}

x (x - 1) (x + Δ x (x + Δ x - 1))

- 3 (6 x + 3 = - 18 x + 9)

(3 x + 1) + (- 7 x + 9)

\frac{( 2 x - 1 )}{( x - 2 ) ( x - 3 ) ( x - 1 )}

What is expand 2((1-4y)/3)^2 ?
The solution to expand 2((1-4y)/3)^2 is (32y^2)/9-(16y)/9+2/9