What are the solutions to the equation 4n^2+5=0 ?

The solutions to the equation 4n^2+5=0 are n=(sqrt(5))/2 i,n=-(sqrt(5))/2 i

Find the zeros of 4n^2+5=0

The zeros of 4n^2+5=0 are n=(sqrt(5))/2 i,n=-(sqrt(5))/2 i

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4 n^{2} + 5 = 0

n = \frac{5}{2} i, n = - \frac{5}{2} i

Solution steps

4 n^{2} + 5 = 0

Move

5

to the right side

4 n^{2} = - 5

Divide both sides by

4

n^{2} = - \frac{5}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = - \frac{5}{4}, n = - - \frac{5}{4}

- \frac{5}{4} = \frac{5}{2} i

- - \frac{5}{4} = - \frac{5}{2} i

n = \frac{5}{2} i, n = - \frac{5}{2} i

2 x^{2} - 15 x y + 25 y^{2}

1000 m^{3} - 27 z^{3}

x^{2} - 26 x - 6 = 0

5 \cdot 1 0^{- 4}

6 x y^{3} z \cdot 3 x^{2} y x^{2}

What are the solutions to the equation 4n^2+5=0 ?
The solutions to the equation 4n^2+5=0 are n=(sqrt(5))/2 i,n=-(sqrt(5))/2 i
Find the zeros of 4n^2+5=0
The zeros of 4n^2+5=0 are n=(sqrt(5))/2 i,n=-(sqrt(5))/2 i