What are the solutions to the equation x^2-26x-6=0 ?

The solutions to the equation x^2-26x-6=0 are x=13+5sqrt(7),x=13-5sqrt(7)

Find the zeros of x^2-26x-6=0

The zeros of x^2-26x-6=0 are x=13+5sqrt(7),x=13-5sqrt(7)

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x^{2} - 26 x - 6 = 0

x = 13 + 57, x = 13 - 57

Decimal Notation

x = 26.22875 \dots, x = - 0.22875 \dots

Solution steps

x^{2} - 26 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 26)^{2} - 4 \cdot 1 \cdot (- 6) = 107

x_{1, 2} = \frac{- ( - 26 ) \pm 10 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 10 7}{2 \cdot 1}, x_{2} = \frac{- ( - 26 ) - 10 7}{2 \cdot 1}

x = \frac{- ( - 26 ) + 10 7}{2 \cdot 1} : 13 + 57

x = \frac{- ( - 26 ) - 10 7}{2 \cdot 1} : 13 - 57

The solutions to the quadratic equation are:

x = 13 + 57, x = 13 - 57

5 \cdot 1 0^{- 4}

6 x y^{3} z \cdot 3 x^{2} y x^{2}

3 x^{2} + 14 x - 24 \leq 0

x^{2} + 2 x - 80

(3 m - 1)^{2} + 12 = 0

What are the solutions to the equation x^2-26x-6=0 ?
The solutions to the equation x^2-26x-6=0 are x=13+5sqrt(7),x=13-5sqrt(7)
Find the zeros of x^2-26x-6=0
The zeros of x^2-26x-6=0 are x=13+5sqrt(7),x=13-5sqrt(7)