What is expand ((8x-1)(2x+3))/4 ?

The solution to expand ((8x-1)(2x+3))/4 is 4x^2+(11x)/2-3/4

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expand ((8x-1)(2x+3))/4

expand

\frac{( 8 x - 1 ) ( 2 x + 3 )}{4}

4 x^{2} + \frac{11 x}{2} - \frac{3}{4}

Solution steps

\frac{( 8 x - 1 ) ( 2 x + 3 )}{4}

Expand

(8 x - 1) (2 x + 3) : 16 x^{2} + 22 x - 3

= \frac{16 x ^{2} + 22 x - 3}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{2} + 22 x - 3}{4} = \frac{16 x ^{2}}{4} + \frac{22 x}{4} - \frac{3}{4}

= \frac{16 x ^{2}}{4} + \frac{22 x}{4} - \frac{3}{4}

Divide the numbers:

\frac{16}{4} = 4

= 4 x^{2} + \frac{22 x}{4} - \frac{3}{4}

Cancel

\frac{22 x}{4} : \frac{11 x}{2}

= 4 x^{2} + \frac{11 x}{2} - \frac{3}{4}

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What is expand ((8x-1)(2x+3))/4 ?
The solution to expand ((8x-1)(2x+3))/4 is 4x^2+(11x)/2-3/4