What are the solutions to the equation 4x^2+6x=-1 ?

The solutions to the equation 4x^2+6x=-1 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4

Find the zeros of 4x^2+6x=-1

The zeros of 4x^2+6x=-1 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4

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4 x^{2} + 6 x = - 1

x = \frac{- 3 + 5}{4}, x = - \frac{3 + 5}{4}

Decimal Notation

x = - 0.19098 \dots, x = - 1.30901 \dots

Solution steps

4 x^{2} + 6 x = - 1

Move

1

to the left side

4 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

6^{2} - 4 \cdot 4 \cdot 1 = 25

x_{1, 2} = \frac{- 6 \pm 2 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 5}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 5}{2 \cdot 4}

x = \frac{- 6 + 2 5}{2 \cdot 4} : \frac{- 3 + 5}{4}

x = \frac{- 6 - 2 5}{2 \cdot 4} : - \frac{3 + 5}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{4}, x = - \frac{3 + 5}{4}

3 h + 7 = 23 - h

\frac{5 x}{11} < 2

\frac{17 - s}{4} = - 10

\frac{3}{2} \cdot 1

- x^{2} + 6 x - 8 \leq 0

What are the solutions to the equation 4x^2+6x=-1 ?
The solutions to the equation 4x^2+6x=-1 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4
Find the zeros of 4x^2+6x=-1
The zeros of 4x^2+6x=-1 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4