What is expand (2x^3-1)/((x^3+1)^2) ?

The solution to expand (2x^3-1)/((x^3+1)^2) is (2x^3-1)/(x^6+2x^3+1)

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expand (2x^3-1)/((x^3+1)^2)

expand

\frac{2 x ^{3} - 1}{( x ^{3} + 1 ) ^{2}}

\frac{2 x ^{3} - 1}{x ^{6} + 2 x ^{3} + 1}

Solution steps

\frac{2 x ^{3} - 1}{( x ^{3} + 1 ) ^{2}}

(x^{3} + 1)^{2} = x^{6} + 2 x^{3} + 1

= \frac{2 x ^{3} - 1}{x ^{6} + 2 x ^{3} + 1}

\frac{14}{3 ( 2 s + 3 )}

\frac{( - 3 - x ) ^{2}}{2}

\frac{a s + b + 3 a + 1}{s ( s + 1 ) ( s + 2 )}

2 a - (x - c)^{2} + y^{2}

(x^{7})^{2}

What is expand (2x^3-1)/((x^3+1)^2) ?
The solution to expand (2x^3-1)/((x^3+1)^2) is (2x^3-1)/(x^6+2x^3+1)