What is expand-((1-x^2)^4)/4 ?

The solution to expand-((1-x^2)^4)/4 is -(x^8)/4+x^6-(3x^4)/2+x^2-1/4

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expand-((1-x^2)^4)/4

expand

- \frac{( 1 - x ^{2} ) ^{4}}{4}

- \frac{x ^{8}}{4} + x^{6} - \frac{3 x ^{4}}{2} + x^{2} - \frac{1}{4}

Solution steps

- \frac{( 1 - x ^{2} ) ^{4}}{4}

(1 - x^{2})^{4} = 1 - 4 x^{2} + 6 x^{4} - 4 x^{6} + x^{8}

= - \frac{x ^{8} - 4 x ^{6} + 6 x ^{4} - 4 x ^{2} + 1}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 4 x ^{2} + 6 x ^{4} - 4 x ^{6} + x ^{8}}{4} = - (\frac{1}{4}) - (- \frac{4 x ^{2}}{4}) - (\frac{6 x ^{4}}{4}) - (- \frac{4 x ^{6}}{4}) - (\frac{x ^{8}}{4})

= - (\frac{1}{4}) - (- \frac{4 x ^{2}}{4}) - (\frac{6 x ^{4}}{4}) - (- \frac{4 x ^{6}}{4}) - (\frac{x ^{8}}{4})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{1}{4} + \frac{4 x ^{2}}{4} - \frac{6 x ^{4}}{4} + \frac{4 x ^{6}}{4} - \frac{x ^{8}}{4}

Divide the numbers:

\frac{4}{4} = 1

= - \frac{1}{4} + x^{2} - \frac{6 x ^{4}}{4} + \frac{4 x ^{6}}{4} - \frac{x ^{8}}{4}

Cancel

\frac{6 x ^{4}}{4} : \frac{3 x ^{4}}{2}

= - \frac{1}{4} + x^{2} - \frac{3 x ^{4}}{2} + \frac{4 x ^{6}}{4} - \frac{x ^{8}}{4}

Divide the numbers:

\frac{4}{4} = 1

= - \frac{1}{4} + x^{2} - \frac{3 x ^{4}}{2} + x^{6} - \frac{x ^{8}}{4}

Rewrite in standard form

= - \frac{x ^{8}}{4} + x^{6} - \frac{3 x ^{4}}{2} + x^{2} - \frac{1}{4}

(10 x + 4) d x

\frac{X ( 1 - X ) ^{3}}{3}

133 \cdot 24

- \frac{( t ^{2} + t ) x + 6 x}{2}

a c (er + f) + a d + b

What is expand-((1-x^2)^4)/4 ?
The solution to expand-((1-x^2)^4)/4 is -(x^8)/4+x^6-(3x^4)/2+x^2-1/4