What is expand ((x+1)^4)/8 ?

The solution to expand ((x+1)^4)/8 is (x^4)/8+(x^3)/2+(3x^2)/4+x/2+1/8

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expand ((x+1)^4)/8

expand

\frac{( x + 1 ) ^{4}}{8}

\frac{x ^{4}}{8} + \frac{x ^{3}}{2} + \frac{3 x ^{2}}{4} + \frac{x}{2} + \frac{1}{8}

Solution steps

\frac{( x + 1 ) ^{4}}{8}

(x + 1)^{4} = x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1

= \frac{x ^{4} + 4 x ^{3} + 6 x ^{2} + 4 x + 1}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} + 4 x ^{3} + 6 x ^{2} + 4 x + 1}{8} = \frac{x ^{4}}{8} + \frac{4 x ^{3}}{8} + \frac{6 x ^{2}}{8} + \frac{4 x}{8} + \frac{1}{8}

= \frac{x ^{4}}{8} + \frac{4 x ^{3}}{8} + \frac{6 x ^{2}}{8} + \frac{4 x}{8} + \frac{1}{8}

Cancel

\frac{4 x ^{3}}{8} : \frac{x ^{3}}{2}

= \frac{x ^{4}}{8} + \frac{x ^{3}}{2} + \frac{6 x ^{2}}{8} + \frac{4 x}{8} + \frac{1}{8}

Cancel

\frac{6 x ^{2}}{8} : \frac{3 x ^{2}}{4}

= \frac{x ^{4}}{8} + \frac{x ^{3}}{2} + \frac{3 x ^{2}}{4} + \frac{4 x}{8} + \frac{1}{8}

Cancel

\frac{4 x}{8} : \frac{x}{2}

= \frac{x ^{4}}{8} + \frac{x ^{3}}{2} + \frac{3 x ^{2}}{4} + \frac{x}{2} + \frac{1}{8}

(a + b)^{2 + (a - b)^{2}}

(s - π)^{2}

C (- 4, - 3) P (4, - 9)

(d u = - 1 d v) \frac{1}{- 1}

(u + 1) u d u

What is expand ((x+1)^4)/8 ?
The solution to expand ((x+1)^4)/8 is (x^4)/8+(x^3)/2+(3x^2)/4+x/2+1/8