What is expand (1+cos(2θ))sqrt(3=sin(2θ)) ?

The solution to expand (1+cos(2θ))sqrt(3=sin(2θ)) is 1*sqrt(3=sin(2θ))+cos(2θ)sqrt(3=sin(2θ))

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expand (1+cos(2θ))sqrt(3=sin(2θ))

expand

(1 + cos (2 θ)) 3 = sin (2 θ)

1 \cdot 3 = sin (2 θ) + cos (2 θ) 3 = sin (2 θ)

Solution steps

(1 + cos (2 θ)) 3 = sin (2 θ)

Apply the distributive law:

a (b + c) = ab + a c

a = 3 = sin (2 θ), b = 1, c = cos (2 θ)

= 3 = sin (2 θ) \cdot 1 + 3 = sin (2 θ) cos (2 θ)

= 1 \cdot 3 = sin (2 θ) + cos (2 θ) 3 = sin (2 θ)

- 2 (2 x - 1 + 1 = 17 - 4 x)

(2 + 6 i,) (- 4 + 3 i,)

((x - 2) (x - 3)) + (x^{2} - 1)

3 (x - 1 = 30)

\frac{4 x ^{2}}{( x + 1 ) ^{2} ( x - 1 )}

What is expand (1+cos(2θ))sqrt(3=sin(2θ)) ?
The solution to expand (1+cos(2θ))sqrt(3=sin(2θ)) is 1*sqrt(3=sin(2θ))+cos(2θ)sqrt(3=sin(2θ))