What is expand ((x+2)(x-1))/((x-4)(x+3)) ?

The solution to expand ((x+2)(x-1))/((x-4)(x+3)) is (x^2+x-2)/(x^2-x-12)

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expand ((x+2)(x-1))/((x-4)(x+3))

expand

\frac{( x + 2 ) ( x - 1 )}{( x - 4 ) ( x + 3 )}

\frac{x ^{2} + x - 2}{x ^{2} - x - 12}

Solution steps

\frac{( x + 2 ) ( x - 1 )}{( x - 4 ) ( x + 3 )}

Expand

(x - 4) (x + 3) : x^{2} - x - 12

= \frac{( x + 2 ) ( x - 1 )}{x ^{2} - x - 12}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{x ^{2} + x - 2}{x ^{2} - x - 12}

(3 x + 5 y = 3, 3) (12 x - 7 y = 51)

ln (q) (- \frac{1}{a} - 1)

(- 3 x - 2) (\cdot + 2)

- \frac{5}{81} (9 e^{9 x} x - e^{9 x})

A^{'} (t) (π (2 - t)^{2})

What is expand ((x+2)(x-1))/((x-4)(x+3)) ?
The solution to expand ((x+2)(x-1))/((x-4)(x+3)) is (x^2+x-2)/(x^2-x-12)