What is expand ((x+1)(x+2))/((x-9)(x+9)) ?

The solution to expand ((x+1)(x+2))/((x-9)(x+9)) is (x^2+3x+2)/(x^2-81)

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expand ((x+1)(x+2))/((x-9)(x+9))

expand

\frac{( x + 1 ) ( x + 2 )}{( x - 9 ) ( x + 9 )}

\frac{x ^{2} + 3 x + 2}{x ^{2} - 81}

Solution steps

\frac{( x + 1 ) ( x + 2 )}{( x - 9 ) ( x + 9 )}

Expand

(x - 9) (x + 9) : x^{2} - 81

= \frac{( x + 1 ) ( x + 2 )}{x ^{2} - 81}

Expand

(x + 1) (x + 2) : x^{2} + 3 x + 2

= \frac{x ^{2} + 3 x + 2}{x ^{2} - 81}

e (x - 3) (x^{2} + 2)^{'}

- h^{2 + (3 R - h) (2 h)}

(1 - x - x^{2})^{7}

\frac{( x - 2 ) x}{( x + 3 ) \cdot 2}

(e^{x} + 1) e^{x} + 2

What is expand ((x+1)(x+2))/((x-9)(x+9)) ?
The solution to expand ((x+1)(x+2))/((x-9)(x+9)) is (x^2+3x+2)/(x^2-81)