What is expand 4(x-2=2(2x-1)) ?

The solution to expand 4(x-2=2(2x-1)) is 4x-8=4x-2

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expand 4(x-2=2(2x-1))

expand

4 (x - 2 = 2 (2 x - 1))

4 x - 8 = 4 x - 2

Solution steps

4 (x - 2 = 2 (2 x - 1))

= 4 (x - 2 \cdot 2 = (2 x - 1))

Apply the distributive law:

a (b - c) = ab - a c

a = 4, b = x, c = 2 = 2 (2 x - 1)

4 x - 4 \cdot 2 = 2 (2 x - 1)

Simplify

4 x - 4 \cdot 2 = 2 (2 x - 1) : 4 x - 8 = 4 x - 2

4 x - 8 = 4 x - 2

(2 x + 2) (ln (x))

\frac{s}{( 2 s + 2 ) ( s - 2 )}

Y^{'} (x) (2 x + 7)^{3}

sin (3) (π - θ)

\frac{( n + 1 ) ^{2}}{2 n ^{2}}

What is expand 4(x-2=2(2x-1)) ?
The solution to expand 4(x-2=2(2x-1)) is 4x-8=4x-2