What is expand \forall x(x^2-x\ne 1) ?

The solution to expand \forall x(x^2-x\ne 1) is \forall x^3-\forall x^2\ne 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand \forall x(x^2-x\ne 1)

expand

\forall x (x^{2} - x \neq = 1)

\forall x^{3} - \forall x^{2} \neq = 1

Solution steps

\forall x (x^{2} - x \neq = 1)

= \forall x (x^{2} - 1 \neq = x)

Apply the distributive law:

a (b - c) = ab - a c

a = \forall x, b = x^{2}, c = x \neq = 1

\forall x x^{2} - \forall xx \neq = 1

\forall x^{2} x - \forall xx \neq = 1

Expand

\forall x^{2} x - \forall xx : \forall x^{3} - \forall x^{2}

\forall x^{3} - \forall x^{2} \neq = 1

\frac{100}{( 1 - x \cdot 10 ) ^{2}}

e^{2 (x - 3)} + e^{- 2 (x - 3)}

\frac{( 2 x - 6 ) ( x + 4 )}{( x + 5 ) ( x - 2 )}

(e^{x} - 1) (e^{x} - x)^{2}

(2 x^{2} + 3 x - 3) e^{x}

What is expand \forall x(x^2-x\ne 1) ?
The solution to expand \forall x(x^2-x\ne 1) is \forall x^3-\forall x^2\ne 1