What is expand (sqrt(9+h)-3)/h ?

The solution to expand (sqrt(9+h)-3)/h is (sqrt(9+h))/h-3/h

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expand (sqrt(9+h)-3)/h

expand

\frac{9 + h - 3}{h}

\frac{9 + h}{h} - \frac{3}{h}

Solution steps

\frac{9 + h - 3}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 + h - 3}{h} = \frac{9 + h}{h} - \frac{3}{h}

= \frac{h + 9}{h} - \frac{3}{h}

23 (x - \frac{π}{6})

so l v e^{7} - 3 (s + 1)

A (- 4, 6) B (3, - 8)

\frac{d}{d y} ((x) (c (y + 1)^{2}))

\frac{t ^{2} ( t + 1 )}{( t - 2 ) ^{3}}

What is expand (sqrt(9+h)-3)/h ?
The solution to expand (sqrt(9+h)-3)/h is (sqrt(9+h))/h-3/h