What is the d/(dy)((x)(c(y+1)^2)) ?

The d/(dy)((x)(c(y+1)^2)) is 2cx(y+1)

What is the first d/(dy)((x)(c(y+1)^2)) ?

The first d/(dy)((x)(c(y+1)^2)) is 2cx(y+1)

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\frac{d}{d y} ((x) (c (y + 1)^{2}))

2 c x (y + 1)

Solution steps

\frac{d}{d y} ((x) (c (y + 1)^{2}))

Treat

c, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x c \frac{d}{d y} ((y + 1)^{2})

Apply the chain rule:

2 (y + 1) \frac{d}{d y} (y + 1)

= 2 (y + 1) \frac{d}{d y} (y + 1)

\frac{d}{d y} (y + 1) = 1

= x c \cdot 2 (y + 1) \cdot 1

Simplify

= 2 c x (y + 1)

\frac{t ^{2} ( t + 1 )}{( t - 2 ) ^{3}}

\frac{8 ( - x + 51 )}{17}

\frac{x ^{2} + 2 x - 2}{( x + 1 ) ( x - 2 )}

(e^{2 t} + e^{- 2 t} + 2)^{2}

(- 5 x - 3) (2 x + 1)^{''}

What is the d/(dy)((x)(c(y+1)^2)) ?
The d/(dy)((x)(c(y+1)^2)) is 2cx(y+1)
What is the first d/(dy)((x)(c(y+1)^2)) ?
The first d/(dy)((x)(c(y+1)^2)) is 2cx(y+1)