What is expand ((x+1)(2x-1))/(2x) ?

The solution to expand ((x+1)(2x-1))/(2x) is x+1/2-1/(2x)

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expand ((x+1)(2x-1))/(2x)

expand

\frac{( x + 1 ) ( 2 x - 1 )}{2 x}

x + \frac{1}{2} - \frac{1}{2 x}

Solution steps

\frac{( x + 1 ) ( 2 x - 1 )}{2 x}

Expand

(x + 1) (2 x - 1) : 2 x^{2} + x - 1

= \frac{2 x ^{2} + x - 1}{2 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 x ^{2} + x - 1}{2 x} = \frac{2 x ^{2}}{2 x} + \frac{x}{2 x} - \frac{1}{2 x}

= \frac{2 x ^{2}}{2 x} + \frac{x}{2 x} - \frac{1}{2 x}

Cancel

\frac{2 x ^{2}}{2 x} : x

= x + \frac{x}{2 x} - \frac{1}{2 x}

Cancel

\frac{x}{2 x} : \frac{1}{2}

= x + \frac{1}{2} - \frac{1}{2 x}

\frac{1}{( x + 3 ) ( x + 2 )}

(- 2 x^{2} y^{3})^{4}

\frac{( x ^{2} + 9 )}{( x - 9 ) ( x - 3 )}

cos (θ) (tan (θ) + sec (θ)) d θ

\frac{x ( x - 2 )}{x + 9}

What is expand ((x+1)(2x-1))/(2x) ?
The solution to expand ((x+1)(2x-1))/(2x) is x+1/2-1/(2x)