What is expand (5x^2-3)(5x^2+3)' ?

The solution to expand (5x^2-3)(5x^2+3)' is 5x^2(5x^2+3)'-3(5x^2+3)'

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expand (5x^2-3)(5x^2+3)'

expand

(5 x^{2} - 3) (5 x^{2} + 3)^{'}

5 x^{2} (5 x^{2} + 3)' - 3 (5 x^{2} + 3)'

Solution steps

(5 x^{2} - 3) (5 x^{2} + 3)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (5 x^{2} + 3)^{'}, b = 5 x^{2}, c = 3

= (5 x^{2} + 3)^{^{'}} 5 x^{2} - (5 x^{2} + 3)^{^{'}} 3

= 5 x^{2} (5 x^{2} + 3)^{^{'}} - 3 (5 x^{2} + 3)^{^{'}}

- \frac{5}{( x - 2 ) ^{2}}

(6 x^{2} - y + 3) d x + (3 y^{2} - x - 2) d y

(e^{3 x} - 4) (e^{3 x} + 6)

\frac{x ( - x + 1 ) ^{3}}{3}

(1 - u^{2})^{2} u^{2} - d u

What is expand (5x^2-3)(5x^2+3)' ?
The solution to expand (5x^2-3)(5x^2+3)' is 5x^2(5x^2+3)'-3(5x^2+3)'