What is expand (xe^{xy}+2xy+1/x)dy ?

The solution to expand (xe^{xy}+2xy+1/x)dy is e^{xy}xdy+2xydy+(dy)/x

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expand (xe^{xy}+2xy+1/x)dy

expand

(x e^{x y} + 2 x y + \frac{1}{x}) d y

e^{x y} x d y + 2 x y d y + \frac{d y}{x}

Solution steps

(x e^{x y} + 2 x y + \frac{1}{x}) d y

= (e^{x y} x + 2 x y + \frac{1}{x}) d y

Distribute parentheses

= d y x e^{x y} + d y \cdot 2 x y + d y \frac{1}{x}

= e^{x y} x d y + 2 x y d y + \frac{1}{x} d y

\frac{1}{x} d y = \frac{d y}{x}

= e^{x y} x d y + 2 x y d y + \frac{d y}{x}

\frac{( 6 A + 2 k + 1 ) ( k + 1 )}{k}

(4 x + 4 δ x) \cdot (x^{2} - 4)

\frac{24}{( s - 2 ) ^{4}}

2 (- 3 x^{2})

\frac{4 x ^{2} - 8 x + 4}{( x + 1 ) ^{2}}

What is expand (xe^{xy}+2xy+1/x)dy ?
The solution to expand (xe^{xy}+2xy+1/x)dy is e^{xy}xdy+2xydy+(dy)/x