What is expand (2^{2n+2}(4+4^n))/5 ?

The solution to expand (2^{2n+2}(4+4^n))/5 is (2^{2n+4})/5+(2^{4n+2})/5

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expand (2^{2n+2}(4+4^n))/5

expand

\frac{2 ^{2 n + 2} ( 4 + 4 ^{n} )}{5}

\frac{2 ^{2 n + 4}}{5} + \frac{2 ^{4 n + 2}}{5}

Solution steps

\frac{2 ^{2 n + 2} ( 4 + 4 ^{n} )}{5}

Expand

2^{2 n + 2} (4 + 4^{n}) : 2^{2 n + 4} + 2^{4 n + 2}

= \frac{2 ^{2 n + 4} + 2 ^{4 n + 2}}{5}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 ^{2 n + 4} + 2 ^{4 n + 2}}{5} = \frac{2 ^{2 n + 4}}{5} + \frac{2 ^{4 n + 2}}{5}

= \frac{2 ^{2 n + 4}}{5} + \frac{2 ^{4 n + 2}}{5}

\frac{d}{d y} ((x) (24 x^{2} + 2 y - 6))

395 X 13

\frac{V ( 2 π - φ )}{( 2 π - 1 )}

s q u a re x (2 x + 1)

\frac{x ^{2} - x}{( x - 2 ) ^{2}}

What is expand (2^{2n+2}(4+4^n))/5 ?
The solution to expand (2^{2n+2}(4+4^n))/5 is (2^{2n+4})/5+(2^{4n+2})/5