What is expand 1-[G_{1}(G_{3}+G_{2})]H_{1} ?

The solution to expand 1-[G_{1}(G_{3}+G_{2})]H_{1} is 1-G_{1}G_{3}H_{1}-G_{1}G_{2}H_{1}

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expand 1-[G_{1}(G_{3}+G_{2})]H_{1}

expand

1 - [G_{1} (G_{3} + G_{2})] H_{1}

1 - G_{1} G_{3} H_{1} - G_{1} G_{2} H_{1}

Solution steps

1 - (G_{1} (G_{3} + G_{2})) H_{1}

Remove parentheses:

(a) = a

= 1 - G_{1} (G_{3} + G_{2}) H_{1}

= 1 - G_{1} H_{1} (G_{3} + G_{2})

Expand

- G_{1} H_{1} (G_{3} + G_{2}) : - G_{1} G_{3} H_{1} - G_{1} G_{2} H_{1}

= 1 - G_{1} G_{3} H_{1} - G_{1} G_{2} H_{1}

\frac{( 25 x + 16 )}{( x ( x + 1 ) ( x + 2 ) )}

(e^{x} - 3) (e^{x} - 4)

z - z^{- 1}

(u + 4) \cdot u^{\frac{1}{3}} d u

\frac{( x + 6 ) ( x + 4 )}{2}

What is expand 1-[G_{1}(G_{3}+G_{2})]H_{1} ?
The solution to expand 1-[G_{1}(G_{3}+G_{2})]H_{1} is 1-G_{1}G_{3}H_{1}-G_{1}G_{2}H_{1}