What is expand (e^x-3)(e^x-4) ?

The solution to expand (e^x-3)(e^x-4) is e^{2x}-7e^x+12

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expand (e^x-3)(e^x-4)

expand

(e^{x} - 3) (e^{x} - 4)

e^{2 x} - 7 e^{x} + 12

Solution steps

(e^{x} - 3) (e^{x} - 4)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = e^{x}, b = - 3, c = e^{x}, d = - 4

= e^{x} e^{x} + e^{x} (- 4) + (- 3) e^{x} + (- 3) (- 4)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= e^{x} e^{x} - 4 e^{x} - 3 e^{x} + 3 \cdot 4

Simplify

e^{x} e^{x} - 4 e^{x} - 3 e^{x} + 3 \cdot 4 : e^{2 x} - 7 e^{x} + 12

= e^{2 x} - 7 e^{x} + 12

z - z^{- 1}

(u + 4) \cdot u^{\frac{1}{3}} d u

\frac{( x + 6 ) ( x + 4 )}{2}

9 x^{2} (\frac{3}{3 x + 3})

\frac{s}{( s ^{2} + 4 ) ( s + 1 )}

What is expand (e^x-3)(e^x-4) ?
The solution to expand (e^x-3)(e^x-4) is e^{2x}-7e^x+12