What is expand (2x^3-1)(x+2)dx ?

The solution to expand (2x^3-1)(x+2)dx is 2x^4dx+4x^3dx-xdx-2dx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^3-1)(x+2)dx

expand

(2 x^{3} - 1) (x + 2) d x

2 x^{4} d x + 4 x^{3} d x - x d x - 2 d x

Solution steps

(2 x^{3} - 1) (x + 2) d x

Expand

(2 x^{3} - 1) (x + 2) : 2 x^{4} + 4 x^{3} - x - 2

= d x (2 x^{4} + 4 x^{3} - x - 2)

Expand

d x (2 x^{4} + 4 x^{3} - x - 2) : 2 x^{4} d x + 4 x^{3} d x - x d x - 2 d x

= 2 x^{4} d x + 4 x^{3} d x - x d x - 2 d x

\frac{e ^{x} ( 2 x - 1 )}{x - 1}

D V (- 5, - 8) y (- 5, - 14)

5 \cdot 7

x y d y - (x^{2} + 2 y^{2}) d x

\frac{5 X ^{2} ( X ^{2} - 6 X + 2 )}{4}

What is expand (2x^3-1)(x+2)dx ?
The solution to expand (2x^3-1)(x+2)dx is 2x^4dx+4x^3dx-xdx-2dx