What is expand (3x^2+9)/((x+3)(x-3)) ?

The solution to expand (3x^2+9)/((x+3)(x-3)) is (3x^2+9)/(x^2-9)

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expand (3x^2+9)/((x+3)(x-3))

expand

\frac{3 x ^{2} + 9}{( x + 3 ) ( x - 3 )}

\frac{3 x ^{2} + 9}{x ^{2} - 9}

Solution steps

\frac{3 x ^{2} + 9}{( x + 3 ) ( x - 3 )}

Expand

(x + 3) (x - 3) : x^{2} - 9

= \frac{3 x ^{2} + 9}{x ^{2} - 9}

e^{(x^{2} + 1)^{3}}

\frac{2 x + 1}{( x + 2 ) ^{2}}

f (t) - f (t - 3) H (t - 3)

\frac{( 2 x - 1 ) ( 2 x + 1 )}{2}

\frac{( - a + 1 )}{a ( a - 2 ) ( a + 1 )}

What is expand (3x^2+9)/((x+3)(x-3)) ?
The solution to expand (3x^2+9)/((x+3)(x-3)) is (3x^2+9)/(x^2-9)