What is expand (2)(-ae^{-2x}+3be^{2x}) ?

The solution to expand (2)(-ae^{-2x}+3be^{2x}) is -2ae^{-2x}+6be^{2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2)(-ae^{-2x}+3be^{2x})

expand

(2) (- a e^{- 2 x} + 3 b e^{2 x})

- 2 a e^{- 2 x} + 6 b e^{2 x}

Solution steps

(2) (- a e^{- 2 x} + 3 b e^{2 x})

Apply the distributive law:

a (b + c) = ab + a c

a = (2), b = - a e^{- 2 x}, c = 3 b e^{2 x}

= (2) (- a e^{- 2 x}) + (2) \cdot 3 b e^{2 x}

Apply minus-plus rules

+ (- a) = - a

= - (2) a e^{- 2 x} + (2) \cdot 3 b e^{2 x}

Simplify

- (2) a e^{- 2 x} + (2) \cdot 3 b e^{2 x} : - 2 a e^{- 2 x} + 6 b e^{2 x}

= - 2 a e^{- 2 x} + 6 b e^{2 x}

tan (e^{5 (2 - y)}) - e^{5 (x - y)}

- 2 (3 x + 4 y = 19)

(lo g_{e} (1 + 2))^{2}

(3 e^{- 5 t} - 15 t e^{- 5 t})^{2}

3 x + 6 x + 12

What is expand (2)(-ae^{-2x}+3be^{2x}) ?
The solution to expand (2)(-ae^{-2x}+3be^{2x}) is -2ae^{-2x}+6be^{2x}